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Count to find the number of 100% 90% 80% in a column
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June 3rd, 2008, 10:00 PM posted to microsoft.public.excel.misc
T. Valko
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Posts: 15,759
Count to find the number of 100% 90% 80% in a column
P.S.
You might have to format the cells as GENERAL or NUMBER.
--
Biff
Microsoft Excel MVP
"T. Valko" wrote in message
...
Follow this pattern:
100%:
=COUNTIF(A1:A10,100%)
90 to 99:
=COUNTIF(A1:A10,"=90%")-COUNTIF(A1:A10,"99%")
80 to 89:
=COUNTIF(A1:A10,"=80%")-COUNTIF(A1:A10,"89%")
70 to 79
=COUNTIF(A1:A10,"=70%")-COUNTIF(A1:A10,"79%")
etc
etc
--
Biff
Microsoft Excel MVP
"% Count" wrote in message
...
I've used the one with the 1 below and it return the 100% ok but I could
not
get the 90%. I need to count the ones between 90 & 100 then 80 to 89
ect...
I'm not sure how to do that.
"T. Valko" wrote:
The column I'm getting the 100% from
is a formula cell that returns this %.
To count entries that equal 100%:
=COUNTIF(A1:A10,"100%")
Or:
=COUNTIF(A1:A10,1)
--
Biff
Microsoft Excel MVP
"% Count" %
wrote in message
...
I've tried different count functions but can't seem to get it right.
I'm
trying to count the number of 100% on 1 line from a column on another
sheet
and the 90%'s on another, 80% ..... The column I'm getting the 100%
from
is
a formula cell that returns this %. Could I please get help with this
formula.
T. Valko
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