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Old April 15th, 2009, 01:01 PM posted to microsoft.public.excel.misc
Fred Smith[_4_]
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Posts: 2,386
Default How do I create formula to calc difference in dates?

Imran,

First, if you have a new query, start a new thread. When you add to an
existing thread, there's too much chance it will get lost.
Second, there are 365 days in a year, not 364. In leap years, there are 366.
Third, you need to be consistent in your date formats. Because the second
date can only be Feb 14/09, the first date must be Dec 10/03, not Oct 12.

So, your actual days in between a
2003: 21
2004: 366
2005: 365
2006: 365
2007: 365
2008: 366
2009: 45
Total: 1893

Regards,
Fred.

"Imran ul Haque" wrote in message
...
sorry but the actual manual calculation is as follows:

Year Days
2003 52
2004 364
2005 364
2006 365
2007 364
2008 364
2009 45
Total days 1918


"Imran ul Haque" wrote:

Can you help me in finding difference of data between 12/10/2003 &
2/14/2009. With datedif or usual cell1 - cell2 formulae it shows 1893
days
where as my manual calculation shows it to be
Year Days
2003 52
2004 360
2005 360
2006 360
2007 360
2008 360
2009 45
Total 1897

Appreciate you help.
Imran


"T. Valko" wrote:

You're welcome. Thanks for the feedback!

--
Biff
Microsoft Excel MVP


"VSlaybaugh" wrote in message
...
Wow! This works great. I appreciate your quick responses when I
submit a
problem I'm having. You always have a solution that works. I just
wish I
understood what you did to make it happen. :-)

"T. Valko" wrote:

Try this:

E16 = start date
F16 = end date

=SUMPRODUCT(--(DAY(ROW(INDIRECT(E16&":"&F16)))=20))

That will count how many 20th of the months there are from a start
date
to
an end date (inclusive).

--
Biff
Microsoft Excel MVP


"VSlaybaugh" wrote in message
...
I have tried this function but am having trouble with it returning
the
right
value. I have an end-date of 1/20/2010 (in cell F16) and a
start-date
of
2/11/2009 (in cell E16). I'm trying to calculate how many
automatic
monthly
transfers there will be on the 20th of each month but the function
is
returning a value of 11 when it should return a value of 12. The
first
transfer will be 2/20/2009 and the last transfer will be
1/20/2010.a
total
of
12 transfers.

"David Biddulph" wrote:

I hope that Dec 2008 - Jan 2006 is 35, rather than 23. :-)

An alternative to DATEDIF would be
=MONTH(A1)-MONTH(B1)+12*(YEAR(A1)-YEAR(B1))
Note that if you have different dates within the start and end
months,
you'll get different results from the 2 formulae.
End of Jan to beginning of Feb gives a 1 month difference with
the
original
=MONTH(A1)-MONTH(B1) and with my extension thereto, but DATEDIF
counts
completed months (with various questions when months are of
unequal
length).
--
David Biddulph

"Ron Rosenfeld" wrote in message
...
On Sun, 30 Dec 2007 18:37:01 -0800, Mike

wrote:

=MONTH(A1)-MONTH(B1)

That works when the two months are in the same year, but what
if
they
are
in
different years? For example January 2008-September 2007 = -8,
but
should
equal 4. Or December 2008-January 2006 = 11, but should equal
23.

Use the undocumented DATEDIF function:

=DATEDIF(B1,A1,"m")

(The first date must be the earlier date).


See http://www.cpearson.com/Excel/datedif.aspx for
documentation.

--ron