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callout dimensions
You guys are a lot of help, this is a great source of how to info. Let me
see if I can stump ya though, because this one has stumped me. I need to programmatically find the dimensions of a callout. The issue I am having is that I can get the top and left and the height and width, but those are the dimensions of the actual circle/bubble and not the line leading to it. If I could find a way to ungroup those two items or find the dimensions of the whole object that would be really helpful. If it is even possible... thanks -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...point/200807/1 |
#2
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callout dimensions
In article 87576a37047e0@uwe, Ccross via OfficeKB.com wrote:
You guys are a lot of help, this is a great source of how to info. Let me see if I can stump ya though, because this one has stumped me. I need to programmatically find the dimensions of a callout. The issue I am having is that I can get the top and left and the height and width, but those are the dimensions of the actual circle/bubble and not the line leading to it. If I could find a way to ungroup those two items or find the dimensions of the whole object that would be really helpful. If it is even possible... thanks Have a look at the shape's .Adjustments collection. Each shape's adjustments may mean different things, but for callouts, if I recall correctly, there are two adjustment values, one is the length of the "pointer" and the other is the angle. The units are inches, I think, but working out the starting point can be a bit wonky. ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com ================================================ Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com |
#3
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callout dimensions
Thanks for the reply, I am using vb.net vs, i can see the adjustments
collection is probably where I could get this type of adjustment, but I cant figure out how to get to that value. I was unable to get to the length or the angle. Is there any way to do this in vs? Steve Rindsberg wrote: You guys are a lot of help, this is a great source of how to info. Let me see if I can stump ya though, because this one has stumped me. I need to [quoted text clipped - 4 lines] whole object that would be really helpful. If it is even possible... thanks Have a look at the shape's .Adjustments collection. Each shape's adjustments may mean different things, but for callouts, if I recall correctly, there are two adjustment values, one is the length of the "pointer" and the other is the angle. The units are inches, I think, but working out the starting point can be a bit wonky. ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com =============================================== = Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...point/200807/1 |
#4
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callout dimensions
In article 87a16cd4b47bb@uwe, Ccross via OfficeKB.com wrote:
Thanks for the reply, I am using vb.net vs, i can see the adjustments collection is probably where I could get this type of adjustment, but I cant figure out how to get to that value. I was unable to get to the length or the angle. Is there any way to do this in vs? Not a clue. But in VBA you examine the shape's .Adjustments(x) You have to work out what the Xth adjustment refers to for each shape type. Steve Rindsberg wrote: You guys are a lot of help, this is a great source of how to info. Let me see if I can stump ya though, because this one has stumped me. I need to [quoted text clipped - 4 lines] whole object that would be really helpful. If it is even possible... thanks Have a look at the shape's .Adjustments collection. Each shape's adjustments may mean different things, but for callouts, if I recall correctly, there are two adjustment values, one is the length of the "pointer" and the other is the angle. The units are inches, I think, but working out the starting point can be a bit wonky. ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com =============================================== = Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com ================================================ Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com |
#5
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callout dimensions
Allright, I'll work with that thanks.
Steve Rindsberg wrote: Thanks for the reply, I am using vb.net vs, i can see the adjustments collection is probably where I could get this type of adjustment, but I cant figure out how to get to that value. I was unable to get to the length or the angle. Is there any way to do this in vs? Not a clue. But in VBA you examine the shape's .Adjustments(x) You have to work out what the Xth adjustment refers to for each shape type. You guys are a lot of help, this is a great source of how to info. Let me see if I can stump ya though, because this one has stumped me. I need to [quoted text clipped - 19 lines] Sept 21-24, San Diego CA, USA www.pptlive.com ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com =============================================== = Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com -- Message posted via OfficeKB.com http://www.officekb.com/Uwe/Forums.a...point/200807/1 |
#6
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callout dimensions
Using adjustments worked, it was just confusing getting to what the value in
each adjustment actually was. Thanks for the help If anyone needs to know: The adjustment represents the distance from the center in terms of the objects size. so a adjustment of .5 horizontally will be half the width from the center of the shape, 1.5 will be 2x the width and so on. The hard part is determining which adjustment is for which value because it seems to change per shape. In a shape with 3 adjustments, the 1st adjustment is the width and the 2nd is the height, but that does not hold for all of the other callouts. ccross wrote: Allright, I'll work with that thanks. Thanks for the reply, I am using vb.net vs, i can see the adjustments collection is probably where I could get this type of adjustment, but I cant [quoted text clipped - 20 lines] Sept 21-24, San Diego CA, USA www.pptlive.com -- Message posted via http://www.officekb.com |
#7
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callout dimensions
Thanks very much for posting your results.
In article 87ae1e1387467@uwe, Ccross via OfficeKB.com wrote: Using adjustments worked, it was just confusing getting to what the value in each adjustment actually was. Thanks for the help If anyone needs to know: The adjustment represents the distance from the center in terms of the objects size. so a adjustment of .5 horizontally will be half the width from the center of the shape, 1.5 will be 2x the width and so on. The hard part is determining which adjustment is for which value because it seems to change per shape. In a shape with 3 adjustments, the 1st adjustment is the width and the 2nd is the height, but that does not hold for all of the other callouts. ccross wrote: Allright, I'll work with that thanks. Thanks for the reply, I am using vb.net vs, i can see the adjustments collection is probably where I could get this type of adjustment, but I cant [quoted text clipped - 20 lines] Sept 21-24, San Diego CA, USA www.pptlive.com ----------------------------------------- Steve Rindsberg, PPT MVP PPT FAQ: www.pptfaq.com PPTools: www.pptools.com ================================================ Live and in personable in the Help Center at PowerPoint Live Sept 21-24, San Diego CA, USA www.pptlive.com |
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