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Can you AVERAGE IF and not null?
I got the answer already, thank you so much!!!
=) "T. Valko" wrote: Try it like this: Array entered. =IF(ISERROR(AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B 10=A2),Data!C1:C10))),"",AVERAGE(IF((Data!A1:A10=B 1)*(Data!B1:B10=A2),Data!C1:C10))) -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... EXCELENT! It worked!!! and how can I hide the #DIV/0! if there are still no scores for that they.. Thank you "T. Valko" wrote: I have a question for Excel 2003 =AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,"")) You can't use entire columns as range references in array formulas in Excel 2003. Use a smaller specific range. Try it like this (array entered**) =AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10)) ** array formulas need to be entered using the key combination of CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER. -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... Hi, I have a question for Excel 2003 =AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,"")) Im trying to get the AVERAGE of this and its giving me a #VALUE! error.. $A2 is the name that is suppose to be equal in the Data! worksheet and B$1 is the date that is suppose to be equal in the Data! worksheet. Im trying to use AND in IF for me to have two logical test.. Can you help me with this? Thank you so much! "JE McGimpsey" wrote: One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN): =AVERAGE(IF((A3:A45="Photo")*(H3:H45""),H3:H45)) In article , "Spottkitty" wrote: =AVERAGE(IF($A$3:$A$45="Photo",H3:H45)) This is the array I'm using to try to determine an average. Problem...if the field is blank it's counting it as zero and lowering the results. It figured 79% when it should have been 94%. 94% was returned using the simple average formula. I'm guessing I need to nest something to not count nulls? Help!!! |
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